Heat of combustion?

Question

Still not getting it.

The combustion of 2.209 grams of elmonane, a hydrocarbon with a molar mass of 218.00 grams/mole, released 44.31 kJ of heat energy. What is the molar heat of combustion for elmonane (kJ/mol)?

For this I worked it out as:
2.209/218= 0.0101mol E (E for elmonane)
44.31/.0101 = 4387.13

But my answer is wrong. What am I supposed to be doing? And what is the right answer?

Maybe that's it, I just couldn't figure out why it was wrong, but it was accepted by a computer, so no partial credit.

Thanks

Answer 1

Your calculation technique is correct, but I didn't round off the moles of E, thereby getting 4374.81 kJ/mol.

Could this be the problem?

Answer 2

I just did the same calculate, also without rounding and got 4372.83 kJ/mol.