How many moles of sodium hydroxide are contained in 1 mL of 5% sodium hydroxide solution?

Question

Assume density of solution is 1.0

What volume of concentrated hydrochloric acid is needed to neutralize this amount of sodium hydroxide solution?

Answer 1

5% means 5 grams of NaOH/100 mL of solution.

So, 1 mL would contain:
1 mL( 5gNaOH/100 mL) = 0.05 grams NaOH

Since the molar mass of NaOH = 40 g/mol, you have

0.05 g / 40 g/mol = 0.00125 mol NaOH.

If you assume that concentrated HCl is 12 M, you'll need

0.00125 M NaOH (1 mol HCl/1 mol NaOH) (1L/12 mol) (1000 mL/L) = 0.10 mL of concentrated HCl to neutralize the solution.

Answer 2

Sodium Hydroxide 5

Answer 3

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