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Find the midpoint of the line segment (1,2) and (5, -2)

2007-11-12 18:43:56 · 9 answers · asked by Anonymous in Education & Reference Homework Help

9 answers

To find the midpoint, you simply determine the halfway point between the two numbers.

For instance, in your example, the two X coordinates are 1 and 5. The number haflway between 1 and 5 is:

(1+5)/2 = 6/2
6/2 = 3

And the two Y coordinates are 2 and -2, so the halfway point is:

(2 + -2)/2 = 0/2
0/2 = 0

So, the midpoint of that line is (3,0).

2007-11-12 18:52:34 · answer #1 · answered by Tim A 1 · 0 0

FIrst, just consider the "x" values
For the points (1, 2) and (5, -2), the "x" values are 1 and 5
What is half way between 1 and 5? Just take the average (5+1)/2 = 3

Now do the same for the "y" values
The "y" values are 2 and -2
So [2 + (-2)]/2 = 0/2 = 0

So our midpoint is (3,0)

2007-11-12 18:49:59 · answer #2 · answered by quietfive 5 · 4 0

I think the answer would be (3,0) . I got this answer by using the midpoint formula...x1+x2/2so 1+5=6/2=3, 2+-2=0

I looked up the formula on the following link
http://regentsprep.org/Regents/math/midpoint/Lmidpoint.htm

2007-11-12 18:59:54 · answer #3 · answered by fattychic 1 · 0 0

3(x+2)-a million = 5 (x-a million) + 3 3x + 6 - a million = 5x - 5 + 3 3x + 5 = 5x - 2 5 + 2 = 5x - 3x 7 = 2x 7/2 = x 2(y+5) - 4 (2y-5) = 3(y-a million) -2 (y-3) 2y + 10 - 8y + 20 = 3y - 3 - 2y + 6 30 - 6y = 3 + y 30 - 3 = y + 6y 27 = 7y 27/7 = y

2016-09-29 03:34:24 · answer #4 · answered by ? 4 · 0 0

(1 + 5)/2 and (2 - 2)/2

6/2 and 0/2

midpoint 3,0

2007-11-12 19:08:17 · answer #5 · answered by Anonymous · 0 0

mid point(x,y)= (x2+x1)/2 ,(y2+y1)/2
= (1+5) /2 , [2+(-2)]/2
= ( 3, 0 )

2007-11-12 18:53:52 · answer #6 · answered by Anonymous · 0 0

add the x's....divide by 2...and you get your x
add the y's....divide by 2...and you get your y
x .... y
(1+5)/2 .... (2-2)/2

(3,0)

2007-11-12 19:06:15 · answer #7 · answered by Anonymous · 0 0

The answer is (3,0).

2007-11-12 19:15:06 · answer #8 · answered by Anonymous · 0 0

(3,0) ??

2007-11-12 18:47:37 · answer #9 · answered by tom4bucs 7 · 1 1

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