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please show me how to work this out, Thanks

2007-11-12 16:43:27 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

You have the following expression:
-8a -b -(-6c) -2a -b -5c

Just plug in the values you are given for a, b and c:

-8(3) -(-2) -(-6(-6)) - 2(3) -(-2) -5(-6)

Now just simplify it all:
-24 + 2 -36 - 6 + 2 + 30

= -22 -42 + 32
= -64 + 32
= -32

Alternatively, you could simplify the expression first, then plug in the values:

-8a -b -(-6c) -2a -b -5c
-8a -b + 6c -2a -b -5c
-8a -2a -b - b + 6c - 5c
-10a - 2b + c

Now plug in a = 3, b = -2, c = -6
-10(3) - 2(-2) - 6
-30 + 4 - 6
-26 - 6
-32

Either way you should get the same answer. Be careful though, because it is easy to lose track of the negative signs.

2007-11-12 16:49:43 · answer #1 · answered by Puzzling 7 · 0 0

-8a-b-(-6c)-2a-b-5c
-8(3) - (-2) - [-6(-6)] - 2(3) - (-2) - 5(-6)
-24 + 2 - (36) - 6 + 2 + 30
-24 + 2 - 36 - 6 + 2 + 30
- 32

2007-11-12 17:31:38 · answer #2 · answered by Namibian 2 · 0 0

= - 8a - b - (- 6c) - 2a - b - 5c
= - 10a - 2b + 6c - 5c
= - 10a - 2b + c
= - 10(3) - 2(- 2) + (- 6)
= - 30 + 4 - 6
= - 32

Answer: - 32

Proof:
= - 8(3) - (- 2) - (- 6[- 6]) - 2(3) - (- 2) - 5(- 6)
= - 24 + 2 - (36) - 6 + 2 + 30
= - 36 + 4
= - 32

2007-11-12 16:54:25 · answer #3 · answered by Jun Agruda 7 · 3 0

a) Multiply so as that one variable cancels out. hence, i'm multiplying the proper equation through 5 & the bottom equation through -a million. 25x-5y=25 -3x+5y=sixty 3 upload those up. 22x=88 Divide through the coefficient. x=4 change this variable in both equations. If y is a similar in both one among them, you're maximum options-blowing. 20-y=5 -y=-15 y=15 12-5y=-sixty 3 -5y=-seventy 5 y=15 the answer is (4, 15). b) that is the position it turns into extra difficult. i visit sparkling up it through a blend of eliminating & substitution. Isolate a variable in a unmarried equation. hence, it will be a contained in the first one. a=b-3c-8 change this in for a contained in the third equation. 3(b-3c-8)+2c=-7 Distribute & combine like words. 3b-9c-24+2c=-7 3b-7c=17 Now i visit take the second one equation, which has a similar variables, & use substitution. 3(2b-c=15) -2(3b-7c=17) 6b-3c=40 5 -6b+14c=-34 11c=11 c=a million change the hot value in for c contained in the unique second & third equations. 3a+2=-7 3a=-9 a=-3 2b-a million=15 2b=16 b=8 verify this contained in the first equation, which has each and each and every of the variables. -3-8+3=-11+3=-8 the answer is (-3, 8, a million)

2016-10-24 03:34:39 · answer #4 · answered by ? 4 · 0 0

first substitute all the numbers in with their coresponding letter.
-8(3)-(-2)-(-6(-6))-2(3)-(-2)-5(-6)
then start to simplify
-24+2-36-6+2+30
and then solve
-22-42+32
-64+32
and -32 is your answer

2007-11-12 16:51:51 · answer #5 · answered by jessi f 2 · 0 1

(-8)(3) + (2) + (6)(-6) + (-2)(3) + (2) + (-5)(-6)
(-24) + (2) + (-36) + (-6) + (2) + (30)
(-22) + (-42) + (32)
(-64) + (32)
-32

2007-11-12 16:54:18 · answer #6 · answered by Anonymous · 0 1

-8(3)-(-2)-[(-6)(-6)]-2(3)-(-2)-5(-6)
-24+2-36-6+2+30
-32

2007-11-12 17:08:30 · answer #7 · answered by razorblade 2 · 0 0

-8(3)-(-2)-[(-6)(-6)]-2(3)-(-2)-5(-6)
-24+2-36-6+2-30
-96+4
-92

2007-11-12 16:49:24 · answer #8 · answered by Anonymous · 0 1

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