I have an aluminum sample of 1.5grams which i calculated to .055 moles. What is the minimum volume of 3.0 M (molar) KOH that would be required to react with this mass of Al?
KOH and Al have a 1:1 mole ratio
2007-11-12 15:58:14 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
We need to dilute the concentrated solution of 3.0 M KOH. We find the volume of KOH that would have 0.55 moles KOH.
Thus:
0.55 mols KOH * (1 L / 3 mol KOH) = 0.1834 L KOH
2007-11-12 16:09:10 · answer #1 · answered by Seraph 2 · 0⤊ 0⤋
Back again, Ms. Alyssa. First, elements "moles" are called "g-atoms". Second, it isn't really clear exactly what reaction would occur. Aluminium is not going to displace K+. However, if you say there is a 1:1 mole ratio, you need to find the volume of 3M KOH that provides 0.055 moles of the base. To do that, the relation is straightforward:
Volume x molarity = moles. or 3V = 0.055
but make sure your volume term is consistent. molarity is moles/liter, so if you have volume in mL, you have to convert it to Liters.
2007-11-13 00:21:33 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋