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whats Differential of e?

2007-11-12 15:50:04 · 7 answers · asked by Komin A 1 in Science & Mathematics Mathematics

7 answers

Yea, I'm not sure what you are asking?

but
d(e) = 0
d(e^x) = e^x
d(e^-x) = -e^-x

2007-11-12 15:57:05 · answer #1 · answered by info2know 3 · 0 0

I'm not sure I understand the question. e is a constant, and you took the derivative of a constant, you get zero.

But the exponential function, e^x is it's own derivative:

d/dx[e^x]=e^x.

It's fairly easy to prove using the definitions of limits. THere's also a proof using power series, but that comes a in a later course.

2007-11-13 00:05:33 · answer #2 · answered by thermodynaman2004 1 · 0 0

If you're talking about the DERIVATIVE of e^x (with respect to x) then it (the derivative) is itself (the very function that you're taking the derivative of): e^x.

If you're talking about some constant e (typically e = 2.7183 in math) then the derivative of a constant with respect to an independent variable is zero.

2007-11-13 00:02:09 · answer #3 · answered by answerING 6 · 0 0

e is a constant: 2.718281828....

Like every other constant, it's derivative is 0. However the derivative of e^x is e^x. Is that what you are asking?

2007-11-12 23:58:39 · answer #4 · answered by John B 6 · 0 0

e

2007-11-12 23:57:30 · answer #5 · answered by Harris 6 · 0 0

e is its own differential

f'(e) = e

the rule for e is....

e^ax, where a is a constant, and x is the variable

f'(x) = a(e^ax)
f''(x) = a[f'(x)] = a[a(e^ax)] = (a^2)(e^ax)

2007-11-12 23:56:17 · answer #6 · answered by jacobrcotton 3 · 0 0

e could be anything. Please make your question more concrete.

2007-11-12 23:55:43 · answer #7 · answered by Jun Agruda 7 · 3 0

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