Geometric Argument?

Question

Use a geometric argument to compute ∫ 1(top) & -2(bottom) f(t) dt where f(t)= |t|

Answer 1

f(t)=|t| is given by f(t)=t for t>=0 and f(t)= -t for t<0. so
∫^1_(-2)f(t)dt
=∫^0_(-2)f(t)dt+∫^1_0f(t)dt
=∫^0_(-2)(-t)dt+∫^1_0tdt
i don't really know what is meant by a "geometric argument" here, but these integrals just compute the area of two triangles, and then you take the sum of these areas to get the value of the original integral. the result is 2+1/2=2.5

Answer 2

Whose on top whose on bottom, whose on first?