As a prize, a contest winner gets to draw out one bill at a time from a box containing 10 five-dollar bills, 10 ten-dollar bills, and 10 twenty-dollar bills. The drawing ends when 3 bills of the same denomination are drawn, and, of course, the contest winner keeps whatever he has drawn. What is the largest sum of money that can be won under these conditions?
2007-11-12 15:47:22 · 6 answers · asked by apples. 4 in Science & Mathematics ➔ Mathematics
(Explain how you got the answer)
2007-11-12 16:05:35 · update #1
$90
2 $5
2 $10
and 3 $20
2007-11-12 15:52:42 · answer #1 · answered by Dustin d 1 · 0⤊ 0⤋
Well you want the 3 bills to be $20. And you could get two of each of the others. So your drawing could look like this:
5,5,10,10,20,20,20 or some form of that. So add them up and you get $90.
2007-11-12 23:57:58 · answer #2 · answered by wayner122 3 · 0⤊ 0⤋
the largest amount would be 2 fives, 2 tens, & 3 twentys
=$90
2007-11-12 23:52:30 · answer #3 · answered by info2know 3 · 0⤊ 0⤋
$90
2007-11-12 23:56:31 · answer #4 · answered by Amy L 2 · 0⤊ 0⤋
two $5 bills
two $10 bills
three $20 bills
add em up and u get 2x5+2x10+3x10=10+20+60=90
2007-11-12 23:55:31 · answer #5 · answered by Harris 6 · 0⤊ 0⤋
= 2($5.00) + 2($10.00) + 3($20.00)
= $10.00 + $20.00 + $60.00
= $90.00
Answer: The largest sum that could be drawn/won is $90.00
2007-11-13 00:00:52 · answer #6 · answered by Jun Agruda 7 · 3⤊ 0⤋