Math = The Sum of two consecutive even integers in 118. What is the 2nd number?

Question

Math Problem =The Sum of two consecutive even integers in 118. What is the 2nd number?

Answer 1

It is obvious that the numbers are one either side of half of 118.

Half of 118 is 59.

The two integers are 58 and 60.

Answer 2

Let the first number be "x"
The next even number is "x+2"
(x) + (x+2) = 118
2x + 2 = 118
2x = 118 - 2 = 116
x = 116 / 2 = 58
There for, second number is 58 + 2 = 60
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Answer 3

x = first even interger
x + 2 = second even integer

sum is addiciton

x + x + 2 = 118
2x = 116
x = 58

so the second number is 58 + 2 = 60 <== answer

Answer 4

even integers are seperated by 2. so...
x+(x+2)=118
we don't need parentheses when adding, so
x+x+2=118
2x+2=118
2x=116
x=58
x is the first number so add two to x (58) to get 60!

Answer 5

x+x+2 = 118
2x = 116
x = 58
x + 2 = 60.
The second number is 60.

Answer 6

n + (n+2) = 118
2n + 2 = 118
2n = 116
n = 58

So the two numbers are 58 and 60

Answer 7

2nd no. : 60
1st no. : 58

58+60= 118

Answer 8

n+(n+2)=118
combine like terms
2n+2=118
subtract both sides by 2
2n=116
divide both sides by 2
n=58

58 is the first.
to get the second, add 2
n+2
58+2=60

Answer 9

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Answer 10

x+y=118
x-y=2
simultaneous equation
y=118-x
x-(118-x)=2
x-118+x=2
2x-118=2
2x=118+2
2x=120
x=60
60+y=118
y=118-60
y=58