how much work does the escalator do to move 1.0(mu)C of charge from the negative terminal to the positive terminal of a 1.5 V battery.
2007-11-12 15:25:13 · 3 answers · asked by biscuits 2 in Science & Mathematics ➔ Physics
I am not aware that escalator move charges. Anyway the work done in moving 1.0(mu)C through 1.5 V of the battery is
Q * V = 1.0(mu)C * 1.5
if (mu) means micro = 10^(-6) = µ
then work done is = W = 1.5 * 1 * 10^-6= 1.5 µJ
2007-11-12 15:34:28 · answer #1 · answered by Venkat R 6 · 3⤊ 0⤋
The work done to move charge over a potential difference is W = q V. You have q and V; multiply them to get the work in Joules.
2007-11-12 15:28:54 · answer #2 · answered by jgoulden 7 · 1⤊ 1⤋
try manipulating the original formula for work [like, W=Fd]. you can substitute F and d from other known formulae that involves coulomb and volts.... or if you want it the easy way, look for special formulae...
2007-11-12 15:31:02 · answer #3 · answered by zai041488 1 · 1⤊ 0⤋