... How long would it take for the to complete the job if they were working together?
2007-11-12 15:03:24 · 8 answers · asked by bricklayer978 1 in Science & Mathematics ➔ Mathematics
Let area to be covered = X units²
Painter A rate of work = X / 4 units² / h
Painter B rate of work = X / 6 units² / h
Combined rate of work = 3X/12 + 2X/12 units²/h
= 5X/12 units² / h
time = area / rate
time = X / (5X/12) h = 12/5 h = 2 2/5 h = 2 h 24 min
2007-11-13 05:23:09 · answer #1 · answered by Como 7 · 2⤊ 1⤋
First, find the number of houses each paints per hour. Painter 1: 1 house / 4 hours = 0.25 houses/hour Painter 2: 1 house / 6 house = 1/6 houses/hour Painter 1 + Painter 2 = 5/12 houses/hour. 1 house / (5 houses/12 hours) = 2.4 hours.
2016-05-22 21:57:06 · answer #2 · answered by joana 3 · 0⤊ 0⤋
Why the hell would they take 5 hours to paint a house if one of them can do it in 4 hours? I don't know the answer to this problem but it's definitely not 5 hours.
O well, I think it's 2 hours.
(1/3)+(1/6)=(1/2)......reciprocal of that is 2. I could be wrong but at least it sounds right.
2007-11-12 15:27:34 · answer #3 · answered by Anonymous · 0⤊ 2⤋
Find the average of the work rate i.e. 4hours and 6hours
(4 + 6)/2
= 10/2
= 5 hours
2007-11-12 15:17:35 · answer #4 · answered by mitsu 2 · 0⤊ 2⤋
4 +6 =10hrs assuming there are 4 sides to this house divide 10 by 4
2007-11-12 15:13:15 · answer #5 · answered by yukonSLT3 3 · 0⤊ 2⤋
I am thinking about 3 hours
2007-11-12 15:12:07 · answer #6 · answered by jb 3 · 0⤊ 2⤋
2.5 hrs i think
2007-11-12 15:07:02 · answer #7 · answered by Qwerty 3 · 0⤊ 1⤋
2.50hrs
2007-11-12 15:12:55 · answer #8 · answered by Edward E 2 · 0⤊ 1⤋