1.5v-6.5w=3.5
0.5v+2w=3
what am i suppose to do?
2007-11-12 13:53:43 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
please explain!? i know that i need to slove for v and w but how?
2007-11-12 13:58:16 · update #1
You have two simultaneous equations in two unknowns.
Decimal numbers have been thrown in for good measure.
1.5v-6.5w=3.5
0.5v+2w=3
Multiply both by 2 to eliminate the decimals:
3v-13w=7
1v+4w=6
Create a common term to eliminate:
Multiply the second equation by 3:
3v+12w=18
Now subtract the first from it:
13w+12w=11
25w=11
w=11/25 or 0.44
Substitute for w in equation 1:
1.5v-6.5*0.44
1.5v=2.86
v=1.9
2007-11-12 15:07:56 · answer #1 · answered by Robert S 7 · 0⤊ 0⤋
elimination method
Multiply the second equation by -3, it becomes -1.5v - 6w = -9
then add it to the first equation
( 1.5v - 6.5w = 3.5)
+(-1.5v - 6w = -9)
-----------------------------
-12.5 w = -5.5
then solve for w
w = -5.5/-12.5 =0.44
then plug this into one of the original equations to solve for v
.5 v + 2(0.44) = 3
v = (3 - (2*0.44))/.5
v = 4.24
2007-11-12 21:57:15 · answer #2 · answered by DC 2 · 0⤊ 0⤋
Scale the equations, then combine them to eliminate one of the unknowns.
Multiply 2nd eqn by 3
1.5v + 6w = 9
subtract this from the 1st eqn:
  1.5v - 6.5w = 3.5
-(1.5v + 6w = 9)
-----------------------
-12.5w = -5.5
Solve for w, then use w to solve for v
2007-11-12 21:59:57 · answer #3 · answered by DWRead 7 · 1⤊ 0⤋
change first equation to 15v-65w=35
multiply seconf equation by -30 to get -15v-60w=-90
now add the two -125w=-55
w=0.44
15v-65(0.44)=35
v=4.24
2007-11-12 21:59:31 · answer #4 · answered by RickSus R 5 · 1⤊ 0⤋
u should probably solve for v and w
2007-11-12 21:56:41 · answer #5 · answered by Zmik 3 · 0⤊ 0⤋