English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

You obtain a mean force reading of 2.33 N pulling on an object with a force sensor. During this time the object moves with uniform motion. Then you suspend the object from the hook of the sensor and obtain a reading of 12.2 N. Assuming the force sensor was properly zeroed, what is the coefficient of kinetic friction between the object and the surface?

2007-11-12 13:48:31 · 2 answers · asked by Hades Lee 2 in Science & Mathematics Physics

2 answers

If the velocity while pulling the object is constant, the net force on it is zero. The tension you pull it with just equally balances the friction. The reading on the force sensor is the tension and therefore is equal to the friction, Ff. The friction equation is
Ff = mu*N
where mu is the coefficient of kinetic friction, and N is the normal force. If the surface it's sliding on is horizontal, then N is the object's weight. If not horizontal, you need the angle to horizontal and you need to use some trig.

When you hang it, you measure the object's weight.

2007-11-12 14:48:37 · answer #1 · answered by sojsail 7 · 0 0

2.33/12.2=.191
guess

2007-11-12 14:07:45 · answer #2 · answered by john 4 · 0 0

fedest.com, questions and answers