need this two equation to solve "Log base 3 (2x+7) = 5" and
Log base 7(2x+7)= Log base 7 (2x+2)
2007-11-12 13:32:36 · 7 answers · asked by rambo 1 in Science & Mathematics ➔ Mathematics
1)
log[3](2x+7) = 5
2x + 7 = 3^5
2x = 243-7 = 236
x = 236/2 = 118
2)
log[7](2x+7) = log[7](2x+2)
since both the logs are to the same base
2x+7 = 2x+2
it has no solution
2007-11-12 13:40:23 · answer #1 · answered by mohanrao d 7 · 0⤊ 0⤋
Log (2x+7) = 5
3
3^5 = 2x+7
I'll let you solve from there =P
2.) If logs have the same base, justt set them equal to eachother
Log base 7(2x+7)= Log base 7 (2x+2)
_________ ________
(2x+7) = (2x+2)
Let you go from there =P
2007-11-12 13:38:47 · answer #2 · answered by mtrxdodge 2 · 0⤊ 0⤋
2x + 7 = 3^5
2x + 7 = 243
2x = 243 - 7
2x = 236
x = 236/2
x = 118
2x + 7 = 2x +2
2x - 2x = 2 - 7
0 = -5
No solution
2007-11-12 13:36:21 · answer #3 · answered by gab BB 6 · 1⤊ 0⤋
With the first equation, raise both sides to the power of 3 getting 2x+7=243. 2x=236, x=118 The second one just set 2x+7=2x+2.
2007-11-12 13:37:34 · answer #4 · answered by Tros 2 · 0⤊ 2⤋
log_3 (2x+7) = 5
implies 2x+7 = 3^5 = 243.
2x = 236
x = 118.
The second equation yields 2x+7 = 2x+2
or 7 = 2, so there is no solution.
2007-11-12 13:51:32 · answer #5 · answered by steiner1745 7 · 0⤊ 0⤋
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2016-12-08 20:11:39 · answer #6 · answered by ? 4 · 0⤊ 0⤋
why dont you put it in the calc.?
the answer is 8.6
2007-11-12 13:35:45 · answer #7 · answered by meee 2 · 0⤊ 1⤋