angular acceleration sorta-help!!!?

Question

If I have a ramp that is 0.285m long at an angle of 17degrees, and a final velocity of 2.38m/s, how can i get the initial velocity????

thanks for your help.... the only problem is that the ramp goes upwards, not down, which probably changes your answer. sorry for the mixup

Answer 1

And what exactly is taking place here ? Hmmm...

I'm assuming the the body moved with an initial velocity Vo when it started to make its way down the ramp.

Ke=Pe

mgh= 0.5mV^2
V= sqrt(2gh)= sqrt(2 x 9.81x 0.285 x sin(17))
V=1.28 m/s
Since linear superposition can be applied
V0= V'-V= 2.38 - 1.28= 1.10 m/s