Factor completely 6x^2(p+q^2)-(p+q^2) ... is this the correct answer?

0 ⤊

6x^2(p+q^2)-(p+q^2)
let u = (p+q^2)

6x^2u-u
(6x^2u-u)/u
6x^2-1

If this is not correct, please explain.

2007-11-12 12:20:22 · 2 answers · asked by Vampy 1 in Science & Mathematics ➔ Mathematics

You can't just divide by u like you did.

6x^2u -u
= u(6x^2u -u)/u
= u(6x^2 -1)
= (p+q^2)(6x^2 -1)

2007-11-12 15:26:12 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋

It's 6x^2u - 1*u = (6x^2-1)u = (6x^2-1)(p+q^2).

2007-11-13 16:59:12 · answer #2 · answered by Curt Monash 7 · 0⤊ 0⤋