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I am given: alpha = 45, a=3, c=4

I have to find beta, gamma, b

please help and explain this step by step, I want to get the idea of how to do these. thanks

2007-11-12 11:17:38 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

So first find gamma by using the law of sines:
sin 45/3 =sin(gamma)/4 so gamma = approx 70.53. then subtract all the angles from 180 degress to get beta. Beta equals 64.47 degrees. then do the law of sines one more time to find b:
sin 45/3=sin(64.47)/b. b=3.83
Check the numbers but thats the gist of how to solve problems like this...

2007-11-12 11:25:46 · answer #1 · answered by Trevor H 3 · 0 0

I assume a is the side opposite angle alpha
a/sin (alpha) =c/sin gamma [Law of sines]
3/sin45 = 4/sin gamma
sin gamma = (4sin45)/3= .942809
gamma = arcsin(.942809) = 70.53 degrees
So Beta = 180 -45 -70.53 = 64.47 degrees
b = asin beta/sin alpha
b = 3sin 64.47/sin 45 = 3.84

2007-11-12 19:40:11 · answer #2 · answered by ironduke8159 7 · 0 0

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