What is the net ionic equation for the following?

Question

1) Fe + CuSO4 ---> FeSO4 + Cu
2) 2 AgNO3 + Cu ---> 2 Ag + Cu(NO3)2
3) BaCl2 + NaSO4 ---> BaSO4 + NaCl2

Please explain how you got each. Thanks for the help!

Answer 1

The detailed procedure is: first write every thing in ionic form; and second cancel ions appeared at both side of the equation, since those are called spectator ions. Once you are skilled, you can easily omit the intermediate step/s.

1) Fe + CuSO4 ---> FeSO4 + Cu
Fe + Cu(2+) + SO4(2-) --> Fe(2+) + Cu + SO4(2-)
Fe + Cu(2+) --> Fe(2+) + Cu (result)

2) 2 AgNO3 + Cu ---> 2 Ag + Cu(NO3)2
2Ag(+) + 2NO3- + Cu ---> 2Ag + Cu(2+) + 2NO3-
2Ag(+) + Cu ---> 2Ag + Cu(2+) (result)

3) BaCl2 + Na2SO4 ---> BaSO4 + 2NaCl
Ba(2+) + 2Cl- + 2Na+ + SO4(2-) ---> BaSO4 + 2Na+ + 2Cl-
Ba(2+) + SO4(2-) ---> BaSO4(s) (result)