f (x) = 4 x ^ (1/2)
f ' (x) = 2 x ^ (- 1 / 2 )
f `(x) = 2 / x^(1/2)
2007-11-16 05:20:28
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answer #1
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answered by Como 7
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4√x = 4(x)^(1/2)
so the derivative is
4(1/2)(x)^(-1/2)
= 2/(√x)
2007-11-12 10:31:10
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answer #2
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answered by bustedtaillights 4
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f(x)=4 √x = 4 x ^(1/2)
f '(x) = (1/2)(4) x^(-1/2) = 2 x^(-1/2)
2007-11-12 10:30:31
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answer #3
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answered by Anonymous
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4/2√x
therefore
2/√x
2007-11-12 10:31:17
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answer #4
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answered by Anonymous
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f(x)=4√x
rewrite the equaiton
f(x) = 4x^(1/2)
d/dx u^n = n * u^(n-1)
f'(x) = 4*1/2 x^(1/2 - 1)
f'(x) = 2x^(-1/2)
f'(x) = 2/√x <== answer
2007-11-12 10:33:38
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answer #5
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answered by Anonymous
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2016-10-24 03:05:31
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answer #6
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answered by ? 4
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Can't quietly remember the equation. But I can help you by doing the chain rule.
2x^ -1/2
2007-11-12 10:32:22
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answer #7
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answered by Anonymous
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http://calc101.com/webMathematica/derivatives.jsp
.. The best derivative website ever
2007-11-12 10:29:41
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answer #8
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answered by Anonymous
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