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if you were to graph this what would its points be so you could graph it.

f (x) = square root symbol 3x-15

please explain how you did it.


were i put the words square root symbol just pretent that's a square root symbol.

2007-11-12 09:25:07 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

Well if x=25, then you would solve the equation for f(x).
f(x) = sqrt ((3*25)-15) = 7.75.

So you would plot the point (25, 7.75) on your graph.

2007-11-12 09:30:06 · answer #1 · answered by WT 4 · 0 0

Just plug in.

sqrt(3*5 - 15) = 0
sqrt(3*6 - 15 = √3
sqrt(3*7 - 15) = √6
sqrt(3*8 - 15) = 3
sqrt(3*9 -15) = √12 = 4√3
sqrt(3*10 -15) = √15
etc

Any x less than 5 will result in f(x) equaling the a square root of a negative number, and thus anything less than 5 won't show up in a real plot. Don't bother testing them.

Just plug in 50 points or so.

2007-11-12 17:31:03 · answer #2 · answered by Edgar Greenberg 5 · 0 0

you would go 2 15 on the y axis because thats your y-intercept. and you would rise 3 and go over 1 from 15 because 3 is your slope and your slope has to be rise over run so thats why you would rise 3 run 1 from 15. keep doing that then draw your line.

2007-11-12 17:44:32 · answer #3 · answered by Anonymous · 0 0

f= -25.98

i have a very smart hightech calculator in 8th grade math
you do

square root symbol 3 times ( -15)=

-25.98

2007-11-12 17:31:22 · answer #4 · answered by Anonymous · 0 0

plug in random numbers till you see the picture and trends....

If your taking calculus:

check your 1st and 2nd derivatives for maxima/minima/concavity

note the points and graph according to those.

If not taking calc ignore the above as it prob made things worse :P

2007-11-12 17:31:11 · answer #5 · answered by james m 3 · 0 0

Regardless of the answer to your math problem,
I would strongly recommend a remedial course in English, as well.

2007-11-12 17:31:18 · answer #6 · answered by skaizun 6 · 0 0

Take three numbers - -2, 0, and 2, and try them. Try a few more to tsee the pattern.

2007-11-12 17:28:28 · answer #7 · answered by Laffmaster 2 · 0 0

unless i am mistaken you have different instructions or did not give us the complete problem

2007-11-12 17:28:36 · answer #8 · answered by lyallalterstuart 3 · 0 0

wow thats hard

2007-11-12 17:28:37 · answer #9 · answered by Paige 2 · 0 0

I have no idea

2007-11-12 17:32:48 · answer #10 · answered by manuelv1 2 · 0 0

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