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the coordinates of the polynomial f(t)=2-t+t^2 relative to the basis B={1, 1+t, 1+t^2}.

2007-11-12 08:07:13 · 2 answers · asked by kondiii 1 in Science & Mathematics Mathematics

2 answers

f(t) = 2 - t + t²

f(t) = a(1) + b(1 + t) + c(1 + t²) = 2 - t + t²

2 - t + t² = 2 - 1 - t + 1 + t² = 2 - (1 + t) + (1 + t²)

a = 2
b = -1
c = 1

The coordinates relative to basis B are (2, -1, 1).

2007-11-12 10:46:33 · answer #1 · answered by Northstar 7 · 0 1

2-t+t^2=1-t+(1+t^2)=2-1-t+(1+t^2)
=2-(1+t)+(1+t^2)
so the coordinates are (2,-1,1)

2007-11-12 08:17:55 · answer #2 · answered by lkjh 3 · 0 0

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