Ok, I can't find the symbols for this problem on here, so i'll try my best. Go here.... http://i30.photobucket.com/albums/c317/teenie_woo/mathproblem.jpg ...I used paint to write it out.
Here's the answers giving to choose from...
r - 3
--------
r + 2
------------------------------------------------------------------------------------
r - 2
-------
r + 2
------------------------------------------------------------------------------
r - 2
-------
r + 3
------------------------------------------------------------------------------
r + 3
-------
r - 2
--------------------------------------------------------------------------------------
r + 3
-------
r + 2
2007-11-12 08:03:30 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
If anyone gets it, can you PLEASE explain to me how you did so. Thanks
2007-11-12 08:12:43 · update #1
(r^2 -5r +6) / (r^2 -4)
[(r-3)(r-2)]/[(r+2)(r-2)]
(r-3)/(r+2)
2007-11-12 08:08:19 · answer #1 · answered by xandyone 5 · 1⤊ 0⤋
The answer is r-3/r+2
2007-11-12 08:14:24 · answer #2 · answered by jack j 1 · 0⤊ 0⤋
= (r-3)(r-2)/[(r-2)(r+2)]
= (r-3)/(r+2) since the (r-2) terms cancel out.
2007-11-12 08:12:00 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
r^2-5r+6
_______
r^2-4
(r-3)(r-2)
_______
(r+2)(r-2)
cancel out both (r-2)
(r-3)
-------
(r+2) <----------- first answer
2007-11-12 08:17:52 · answer #4 · answered by mm 2 · 0⤊ 0⤋