I have a TI-89, and i need help on graphing. i need to be able to graph the following: y=sinθ for (-13/2) ≤ x ≤ -(8π/3)
y=cosθ for (-9π/4) ≤ x ≤ (π/4)
I forgot how to graph these, and i am trying to review for a test. thanks!
2007-11-12 05:43:09 · 3 answers · asked by missyjc12 2 in Science & Mathematics ➔ Mathematics
y1 = sin x Window min = -13/2, max = -8π/3, scale = π/12
y2 = cos x Window min = -9π/4, max = π/4, scale =π/12
2007-11-12 05:53:53 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
- - - W - O - W - - -
First, locate (-9Ï/4) and (Ï/4) on your line.
...../...\.......x . . . . . ../
...........\.....| . . . . .. /
.............\.. |. . . . . ./
----*-----------\|----------/--*---------------- y y=cosθ
(-9Ï/4).........|\......./.....(Ï/4).
...............0.. .\. .../
.................. ....\./
FYI: this graph not to scale.
( - - - - - - - - - 2Ï- - - - - - - -) it needs to be 2Ï, long
-9Ï/4 + Ï/4 = 2Ï
period is 2Ï so its full 360degree cycle
wow, your pritty smart,, this is hard math... Trig.
its hard to graph this here... try to go back to that chapter section.
2007-11-12 13:47:07 · answer #2 · answered by Dr. Seb 2 · 0⤊ 0⤋
well you are smarter than me . good luck on your test
2007-11-12 13:46:53 · answer #3 · answered by cindy k 2 · 0⤊ 1⤋