how do i solve for t in this equation.
0 = -4.9t^2 + 24.5t + 68.6
2007-11-12 05:40:31 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(4.9^2-68.6)/24.5=t
2007-11-12 05:45:11 · answer #1 · answered by CinnamonGirl777 4 · 0⤊ 1⤋
-4.9t^2 + 24.5t + 68.6 = 0
4.9t^2 - 24.5t - 68.6 = 0
divide by 4.9
t^2 - 5t - 14 = 0
t^2 - 7t + 2t - 14 = 0
t(t-7) + 2(t-7) = 0
(t-7)(t+2)=0
t = 7 or -2
2007-11-12 05:50:07 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
0 = -4.9t^2 + 24.5t + 68.6
t^2 - 5t -14 = 0
(t-7)(t+2) =0
t = 7 or t= -2
2007-11-12 05:45:15 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
-4.9t^2 + 24.5t + 68.6= 0
t^2+t=0-68.6/24.5/-4.9
t^2+t=0.57
t+t=square root of 0.57
2t=0.75
t=0.75/2
t=0.38
2007-11-12 05:48:40 · answer #4 · answered by seeleeree 3 · 0⤊ 0⤋
get t by itself
1) -4.9t^2+24.5t= -68.6
2) -4.9t^2+t= -2.8
3) t^2+t = .57142857
hope that helps
2007-11-12 05:51:41 · answer #5 · answered by Anonymous · 0⤊ 0⤋
DIVIDE THE FULL EQUATION BY -4.9
WE GET
t^2 - 5t -14 =0
t^2-7t+2t-14=0
t(t-7)+2(t-7)=0
(t-7)(t+2)=0
t=7 or -2
2007-11-12 05:45:57 · answer #6 · answered by maddygatz 1 · 0⤊ 0⤋
the LCM must be x(x+5) so... {(x+3)(x+5)-(x)(x+2) - (x+5)} / (x)(x+5) = 0 (x^2 +8x + 15 - x^2 - 2x -x - 5) / (x)(x+5) = 0 (5x + 10) / (x)(x+5) = 0 see you later as x isn't 0 or -5 (those can make the denominator 0)... 5x+10 = 0 x = -2 wish this facilitates! :) best of success.
2016-10-24 02:40:18 · answer #7 · answered by ? 4 · 0⤊ 0⤋
If you have a graphing calculator graph the function and see where it intersects the x axis. you will have two answers. or you can use the quadratic eqation. first one is easier though.
your answers are -2 and 7
2007-11-12 05:45:41 · answer #8 · answered by DDDD 2 · 0⤊ 0⤋