The inside diameters of the larger portions of the horizontal pipe in Figure P9.47 are 2.40 cm. Water flows to the right at a rate of 1.60 10-4 m3/s. Determine the inside diameter of the constriction.
http://www.webassign.net/sf/p9_47.gif
2007-11-12 04:55:28 · 1 answers · asked by Burton 1 in Science & Mathematics ➔ Physics
1.453567 cm. There's a calculator at the ref. page. The solution is complicated by the fact that the manometers measure head relative to the radii of the two sections, not relative to a constant level such as the center line of the pipe. So some iteration was needed such that the pressure difference P2-P1 was equivalent to a head of (r2+5 cm) - (r1+10 cm) = -0.536375 kPa.
Note two parameters used by the ref.:
g = 9.8 m/s^2
A velocity^2 scaling term of 4/3 is used, so to agree with this result the straight Bernoulli equation must be adjusted by this factor; specifically by using the term 4/3*v^2/2 in place of v^2/2.
2007-11-13 09:24:11 · answer #1 · answered by kirchwey 7 · 1⤊ 0⤋