What volume of O2 (m3) is needed for the complete combustion of 152 g of C2H6 at 16.0oC and 100.0 kPa?

Question

Enter a numeric answer only, no units.

Answer 1

Write an equation for combustion of ethane.
C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
Determine MOLES of ethane
152/30 g/g-mole = 5.1 appx.
From reaction for each mole of ethane, 7/2 mole of O2 is needed. By proportion
1/(7/2) = 5.1/X and X= 17.8 moles appx.
Now find volume at given TP of 17.8 moles of O2.