In each of the four legs of the relay, a dog jump over a hurdles, retrieve a ball from the fly box, and runs back over the hurdles. In the last leg of the relay, the collies start the course 0.3 second before the sheep dog. The collies is running 23.4 feet per second, and the sheep dog running 24 feet per second. The distance from where the dog start to the fly box is 150 ft. Let t represent the time it take the collies to run the last leg . Write an equation to find the number of seconds after which the sheep dog would catch up with the collies.
Help me please, i'm so confused!
This is what i wrote , is it right?
150 * 23.4x = 150 * 24x - 0.3
2007-11-12 03:50:21 · 1 answers · asked by (: 3 in Science & Mathematics ➔ Mathematics
distance = rate * time
You are asked to find the time at which the dogs have run the same distance. If t denotes the amount of time that the sheep dog has run, then (t + 0.3) is the amount of time that the collie has run. If they run the same distance (at which time the sheep dog catches up with the collie), then
23.4(t + 0.3) = 24t
Solve for t.
2007-11-12 04:28:46 · answer #1 · answered by Ron W 7 · 0⤊ 0⤋