a girl coasts down a hill on a sled, reaching level ground at the bottom with a speed of 6.8 m/s. The coefficient of kinetic friction between the sled's runners and the hard, icy snow is 0.044, and the girl and sled together weigh 651 N. A=9.81 m/s^2.
a) How far does the sled travel on the level ground before coming to a rest?
b) What is the coefficient of kinetic friction b/w the block and the incline?
c) What is the magnitude of the frictional force acting on the block?
d) what is the speed of the block after it slides the distance of 2.67?
2007-11-12 03:19:53 · 1 answers · asked by ? 2 in Science & Mathematics ➔ Physics
a) Use the given mass and velocity of the sled-girl system to calculate its kinetic energy at the bottom of the hill. Remember, KE = 0.5*mv^2. Then use the mass and the coefficient of kinetic friction to calculate the force of friction acting on the sled-girl system. Use the formula Ff = umg, where u is the coefficient of friction. Finally, use the definition of work, W = Fx, to find the distance x that the sled must travel for friction to do negative work on it equal to the kinetic energy it previously had.
Unfortunately, I cannot answer b), c), or d), because you have not provided any information about a block.
2007-11-14 08:04:11 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋