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A phonograph record has an initial angular speed of 33 rev/min. The record slows to 10 rev/min in 1.7 s. What is the record's average angular acceleration during this time interval?

2007-11-12 02:47:54 · 2 answers · asked by Jon Johanson 1 in Science & Mathematics Physics

2 answers

Av. angular acceleration
= [(10/60) - (33/60)]/1.7 rev/s^2
= - 0.2255rev / s^2 or - 1.420radians / s^2

2007-11-12 03:02:27 · answer #1 · answered by Tim C 7 · 0 0

Av. angular acceleration
= (10*60 - 33*60)/1.7 rev/s^2
= - 811.8 rev / s^2

2007-11-12 02:54:37 · answer #2 · answered by Madhukar 7 · 0 0

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