Find the number of ways in which 6 teachers can be assigned to 4 sections of a probality class if no teacher?

Question

is assigned to more than once section?
Explain how... thanks

Answer 1

If it's just a question of which group of teachers get a section, 6C4 = (6•5)/(1•2) = 15, but if the sections are distinct, eg. math 101, math 211, etc., then it's 6•5•4•3 = 360.