-e^(-x)
Any integral e^(b) is e^(b) * the derivative of b.
2007-11-12 01:56:42
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answer #1
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answered by theopratr 3
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Integral ( e^(-x) dx )
Advanced Calculus students can do this mentally, but here is how to solve this by hand. Using substitution.
Let u = -x. Then
du = (-1)dx, so
(-1)du = dx
Integral ( e^u (-1) du )
Factor out the (-1) to get
(-1) Integral ( e^u du)
And now, the integral is easy
(-1)e^u + C
back-substitute,
(-1)e^(-x) + C
2007-11-12 09:59:56
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answer #2
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answered by Puggy 7
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d/dx e^x = e^x
Proof of e^x : by ln(x)
Given : ln(x) = 1/x; Chain Rule; x = 1.
Solve:
(1) ln(e^x) = x = 1
ln(e^x) = ln(u) e^x (Set u=e^x)
= 1/u e^x = 1/e^x e^x = 1 (equation 1)
e^x = e^x
Discussion of
Integral e^x dx = e^x + C
1. Proof
Since we know the derivative: ex = ex,
we can use the Fundamental Theorem of calculus:
e^x dx = (e^x) dx = e^x + C
since the coefficient of x is -1.
answer is
-e^-x + C
2007-11-12 10:02:34
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answer #3
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answered by Anonymous
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-e^(-x) according to my TI-89.
2007-11-12 09:57:48
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answer #4
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answered by Philo 7
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-e^-x + C
2007-11-12 10:38:24
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answer #5
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answered by Joe L 5
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