Sprinfs - oscillation?

Question

A spring is hung from the ceiling. When a block is attached to its end, it stretches 2.0 cm before reaching its new equilibrium length. The block is then pulled down slightly and released.

What is the frequency of the oscillation?

Answer 1

Since angular frequency w is related to frequency f and ...
w=2 pi f=sqrt(k/m)
k- spring constant
m- attached oscillating mass

Also we know that as the mass m was attached the spring has extended a distance x

mg= kx then
k/m = g/x or
sqrt(k/m) = sqrt( g/x)

now since

w=2 pi f=sqrt(k/m)
f=(1/2pi)sqrt(g/x)
f=(1/2pi) sqrt(9.81 / 0.02)=
f=3.52 Hz