Make sure you give me an equation too.
2007-11-10 12:08:07 · 15 answers · asked by Kaya J 1 in Science & Mathematics ➔ Mathematics
3x + 6x = x + 5
9x = x + 5
8x = 5
x = 5/8
2007-11-10 12:10:35 · answer #1 · answered by Mavis 5 · 0⤊ 1⤋
Once, right after 0 and before 2. Or do you mean "How many times does the numeral "1" appear in a list of all the numbers between 0 and 999,000?" I would approach that problem by saying that there are 10000 numbers in that interval that end in 1 there are 1000 numbers in that interval that have 1 in the ten's place and none in the units place. etc. And then I'd worry about eliminating the leading 0's from my count.
2016-05-29 03:25:39 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Let the number be "x:"
By statement,
3x + 6x = x + 5
9x =x + 5
8x = 5
x = 5/8 = .625
===========
Verification:
3* .625 + 6*.625 = .625 +5
1.875 + 3.75 = 5.625
5.625 = 5.625
===========
2007-11-10 14:25:03 · answer #3 · answered by Joymash 6 · 0⤊ 0⤋
3x + 6x = x + 5
9x = x + 5
8x = 5
x = 5/8
2007-11-10 12:12:54 · answer #4 · answered by Emily Y 2 · 1⤊ 0⤋
.625
3x + 6x = x + 5 combine like terms
9x = x + 5 subtract x from both sides
8x = 5 divide both sides by 8
x = 5/8 or .625
2007-11-10 12:14:42 · answer #5 · answered by Lisa C 2 · 0⤊ 0⤋
[02]
Let the number be x
According to the problem,
3x+6x=x+5
9x=x+5
9x-x=5
8x=5
x=5/8
Therefore,the no is 5/8
2007-11-10 12:12:22 · answer #6 · answered by alpha 7 · 0⤊ 0⤋
3x + 6x = x + 5
x=5/8
2007-11-10 12:10:39 · answer #7 · answered by tinhnghichtlmt 3 · 0⤊ 0⤋
3x+6x=x+5
9x=x+5
8x=5
x=5/8
2007-11-10 12:25:01 · answer #8 · answered by Harris 6 · 0⤊ 0⤋
3x+6x=x+5
9x=x+5
8x=5
x=5/8
2007-11-10 12:11:03 · answer #9 · answered by Anonymous · 0⤊ 0⤋
3x+6x=x+5
Grouping 9x=x+5
Subtract x from both sides 8x=5
x= 5/8
2007-11-10 12:26:23 · answer #10 · answered by Truth 7 · 0⤊ 0⤋