2007-11-10 12:04:22 · 7 answers · asked by jlmeritt 1 in Science & Mathematics ➔ Mathematics
[01]
2w^2+3w-14
=2w^2-4w+7w-14
=2w(w-2)+7(w-2)
=(w-2)(2w+7)
2007-11-10 12:09:17 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
I assume you need to factorize the expression
2w^2 + 3w - 14 = (2w +7)(w - 2)
2007-11-10 20:08:32 · answer #2 · answered by norman 7 · 0⤊ 0⤋
Now that everyone has given you the answer, can I explain how you can do it without so much guessing and checking? For ax^2+bx+c ... multiply a times c (in this case -28), now find two numbers that have a sum equal to b (in this case 3). So, you can pretty easily figure out that the two numbers you want are 7 and -4... Take these two numbers and write two fractions with 7 and -4 as the numerators and a (in this case 2) as the denominator of both fractions.
So, you now have 7/2 and -4/2. Reduce each, if possible...
7/2 and -2/1.
FINALLY, write your binomials from the bottom up, if you will (put another way, for E/F, the binomial to write is (Fx+E), giving us (2x+7)(x-2).
Pretty cool, huh? Don't know they don't teach this in textbooks.
2007-11-10 20:30:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
what's ur question?
If solve the prob
2w^2 + 3w - 14 = 0
delta = 3^2 - 4*2*(-14) =121
--> w= (-7/2) or 2
2007-11-10 20:09:17 · answer #4 · answered by tinhnghichtlmt 3 · 0⤊ 0⤋
What should we do ?????????Factorize??? Solve ???
Anyway This will be factorized.
2w² + 3w - 14
Split the middle term,
2w² - 4w +7w - 14
2w(w-2) + 7(w-2)
(w-2)(2w+7)
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2007-11-10 22:49:06 · answer #5 · answered by Joymash 6 · 0⤊ 0⤋
w=2,-7/2
2007-11-10 20:09:03 · answer #6 · answered by Anonymous · 0⤊ 0⤋
do you want to factor it? I'll assume you do:
(2w +7)(w - 2)
that's all!
2007-11-10 20:09:12 · answer #7 · answered by Marley K 7 · 0⤊ 0⤋