If I have 41g of 2Ca3(PO4)2, how many moles of P4O10 will form?

Question

The 3,4,2and 10 are subscripts. How do I figure this out?

Answer 1

This is a chemistry question.
But...What do you mean about "2" in front of "Ca3(PO4)2"?
I can help you assume this "2" is your typo, and assume that you use phosphor from Ca3(PO4)2 to form P4O10.
The molar mass of Ca3(PO4)2 is 310.18 g/mol.
The molar mass of P4O10 is 283.889 g/mol.
41g Ca3(PO4)2 = 0.132 mole Ca3(PO4)2 ==> 0.264 mole P atoms ==> 0.066 mole P4O10 to be formed = 19g P4O10 to be formed.