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i need help =[
okay so it's


\5/64x^10 / \5/2x^3

the \/ is the square root sign and the / is a division bar..

basically, it is 64x^10 to the 5th root divided by 2x^3 to the fifth root.

my question is, how do you rationalize the denominator? i know you multiply it by x^2 but do you do anything to the two?

thanks so much

2007-11-10 08:37:21 · 2 answers · asked by kim 2 in Science & Mathematics Mathematics

2 answers

Write it like this to make it clearer and easier:
[(64x^10)^(1/5)]/(2x^3)^(1/5)
= [(2*2^5x^10)^(1/5)]/(2^(1/5)x^(3/5))
= [2^(1/5)*2x^2]/(2^(1/5) x^(3/5))
= 2x^2/x^(3/5)
= 2x^(7/5)

2007-11-10 08:52:36 · answer #1 · answered by ironduke8159 7 · 1 0

You need to multiply the 2 by 16, so that it will equal 32... that way when you find the 5th root, it will be a whole number. So multiply the whole thing by 16x^3

2007-11-10 16:53:19 · answer #2 · answered by peachmonk 4 · 0 1

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