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A pendulum of length L1 has a period T1 = 0.9 s. The length of the pendulum is adjusted to a new value L2 such that T2 = 1.1 s. What is the ratio L2/L1?

2007-11-10 06:37:04 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

I'm assuming a simple pendulum where
T=2pisqrt(L/g)

then

L= T^2g/(2pi)^2

L2/L1= (T2/ T1)^2
L2/L1= (1.1/ 0.9)^2= 1.5

2007-11-10 08:08:25 · answer #1 · answered by Edward 7 · 0 0

This answer assumes that the pendulum rod is likewise made up of brass..In practice brass isn't used for pendulum rods of that length. The bob could be brass yet in an basic pendulum the rod is greater in all probability made up of metallic or wood. it relatively is the enlargement of the rod that has the wonderful result on timing. in basic terms for the checklist :-)

2016-10-16 00:55:12 · answer #2 · answered by lumley 4 · 0 0

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