n+x=32; n*x=48. What is the sum of the reciprocals of the two numbers? State as a common fraction?

Question

Please explain

Answer 1

1/x + 1/n = n/xn + x/xn = (x+n)/xn = 32/48 = 2/3

Answer 2

if n+x=32;
then x = 32-n
substitute that into the secodn equation
n(32-n)=48.
32n -n sqared = 48
take over to right hand side
0= n ^ 2 -32n +48
now solve for x
usig nwhatever method.

then find n and then x
work out (1/n)+(1/x)

Answer 3

1/32 +1/48 = 3/96 + 2/96 = 5/96
= 1/(n+x) +1/nx = (nx+n+x)/(nx(n+x))

Answer 4

If the two number are (n+x) and (n*x), then iron duke is correct.
If the two numbers are x and c, then the answer following his is correct (but it is not finished and the answers to x and n are not whole numbers...the answer is quite messy).
Good luck!