Which of the ordered pairs (5,5),(-5,0) and (-5, -5) can be found in the shaded solution area for the system of inequalities below? (The ordered pair must be in the double shaded region or it is not a solution of the system.)
x + 3y <-6
-3x + y >= 4
2007-11-10 05:56:06 · 2 answers · asked by Angelkins 3 in Education & Reference ➔ Homework Help
The previous answer is correct. However, the quick way would be to simply plug those values into the inequalities in their original forms and determine whether the the result is true or false. Only the pairs that result in "true" for both are correct answers.
2007-11-10 06:41:41 · answer #1 · answered by Tim C 7 · 0⤊ 0⤋
First, algebraically solve for Y by moving the X's and isolating Y. Then plug those inequalities into your calculator:
Y < (-6 - X) / 3
Y >= 4 + 3X
you'll get two linear lines... plug in (0,0) into your original inequalities and you'll see that they both fail. (-6 is not greater than 0 and 0 is not greater than or equal to 4)
pretty much, you'll find that the solution is in a large part of quadrant 3.
The answer is (-5, -5)
2007-11-10 14:12:11 · answer #2 · answered by pWnFuL 2 · 0⤊ 0⤋