I have homework for Calculus and I'm stuck on this problem.
2007-11-10 05:55:52 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Thanks Everyone!
This really helped me a lot
:)
2007-11-10 06:19:09 · update #1
3x^2 - x^3
-3x^2+6x
2007-11-10 06:00:22 · answer #1 · answered by robert 6 · 0⤊ 0⤋
that would equal 3X^2-X^3 and the derivative of that is 6X-3X^2 ;-)
2007-11-10 14:01:49 · answer #2 · answered by Stephen R 2 · 0⤊ 0⤋
u=x^2
v=(3-x)
udv+vdu is the derivative (product rule)
x^2 (-1) +(3-x) 2x
-x^2+6x-2x^2
-3x^2+6x
2007-11-10 14:04:17 · answer #3 · answered by cidyah 7 · 0⤊ 0⤋
multiply through
3x^2-x^3
then derive
Subtract one from the exponent, then multiply by the new exponent
so... 3x - (x/2)^2
2007-11-10 14:01:57 · answer #4 · answered by Joe M 1 · 0⤊ 0⤋
if x^2 * (3-x) then
you may use distibutive property first.
or
the derivative is
2x(3-x)+(-x)x^2)
that is
=6x-6x^2-x^3
Hint: (u.v)'=u'v+v'u
2007-11-10 14:02:37 · answer #5 · answered by iyiogrenci 6 · 0⤊ 0⤋
ok..
f'(x)=x^2(3-x)
f'(x)= x^2 dx (3-x) + x^2 [(3-x)dx]
f'(x)= 2x(3-x) + x^2
f'(x)= 6x-2x^2 - x^2
f '(x)= -3x^2 + 6x
f '(x)= -3x(x-2)
2007-11-10 14:05:45 · answer #6 · answered by ejay 2 · 0⤊ 0⤋