Can anyone help me with Kepler's Third Law ansd the Mass of Jupiter question?

Question

Converting into Earth Years:
Period; 1.69150 days divided by 365=0.004634327 (So this is my P)

Converting radius in AU:
Amplitude; 2.8674 into 1050= 0.002730857 (And this is my A)

Then take A^3= 0.00000002

Then take P^2= 0.000021477

Then take A and P and divide it, which equals to= 0.000948251 (Which I suppose is M?)

Ok up until now do you think I’m right? And these are the next steps one guy told me to do not sure if it’s right or not.

Take the answer of 0.000948251 and multiply it with the mass of sun, 2x10^30. Which equals to = 1.89650283 to the power of 27.

Then take that number and multiply it with 10^27, which equals to 1.89650283^54.

So is my answer then the last one? And here's the question Im being asked: If your answer is 2.0, your calculations say Jupiter is twice as massive as the Sun, if you get 0.005, then Jupiter is 1/200th of the mass of the Sun. Does your answer make sense?

**Also I came up with the P and A from the observation of the Io moon I made using a program...so that part I know is right. I just need to know what exactly is the questing asking?

Here's the 1st line of it: Use the equation to find Jupiter's mass in solar units (that is Jupiter's mass divided by the mass of the Sun).

This is the QUESTION: (I have copied the exact words)

Use the equation to find Jupiter's mass in solar units (that is Jupiter's mass divided by the mass of the Sun). If your answer is 2.0, your calculations say Jupiter is twice as massive as the Sun, if you get 0.005, then Jupiter is 1/200th of the mass of the Sun. Does your answer make sense?

Answer 1

Newton's theory of gravitation tells us that A^3/P^2 will be proportional to the central mass, for a small orbiting body. This isn't really Kepler's law - he only stated it for the specific case of objects orbiting the Sun, where he observed that A^3/P^2 is a constant.

It sounds like that ratio is what they're asking for; that's your 0.000948251. Multiplying that by the mass of the Sun should give you the mass of Jupiter. Multiplying that by 10^27 means you're lost.

Answer 2

Makes no sense at all.

Answer 3

But what's the *question*?