A projectile is fired from a ship comes down 10s after firing and hits the water 6000m from the ship...?

Question

1) what is its horizontal velocity?

2) At what times did it reach the highest point?

3) What was its max altitude?

4) What was its vertical component?

Answer 1

dude.. did u atleast try? ur asking too many problems and they are all related. ask one and u could do the rest!

Answer 2

1) s = Vxt
Vx = 6,000/10 = 600 m/s
2) t = T/2
t = 10/2 = 5 s
3) h = h0 + Vy0t +(1/2)gt^2
0 = h0 + 0*5 - (1/2)(9.80665)5^2
h0 = 122.58 m
4) Vy = Vy0 - gt
Vy0 = (9.80665)(5)
Vy0 = 40.033 m/s