F(x)=3/((e^-5x)-4)
2007-11-10 03:35:18 · 4 answers · asked by samantha 5 in Science & Mathematics ➔ Mathematics
As x increases. the term (e^-5x) gets smaller and smaller, approaching 0. Therefore, the horizontal asymptote is -3/4.
2007-11-10 03:48:37 · answer #1 · answered by Computer Guy 7 · 0⤊ 1⤋
Subsitute in +/- â for x.
F(â) = 3 / (e^(-â)-4)
= 3 / [(1/e^â)-4]
= 3 / (0 - 4)
=-3/4
=> if x is large, F(x) < -3/4, (approaches 3/4 from below)
F(-â) = 3 / (e^â-4)
= 3 / â
= 0
=> if x is large and negative, F(x) > 0 (approaches 0 from above)
2007-11-10 12:48:39 · answer #2 · answered by Helen B 5 · 0⤊ 0⤋
e^(-5x)-4=0
e^(-5x) = 4
-5x = ln(4)
x=-0.2 ln(4)
This is parallel to the x axis. It is below the x axis.
2007-11-10 11:41:22 · answer #3 · answered by Sciman 6 · 0⤊ 0⤋
the curve is asyptotic to the line y = -0.75 as x approaches infinity and to the line y = 0 as x approaches - infinity.
2007-11-10 12:01:22 · answer #4 · answered by swd 6 · 0⤊ 0⤋