please solve?

Question

ok i am doing Cambridge maths and this annoys me i understand when the topic is taught but after i can't apply it in real questions. i kno the answers but i dont know how to get them (like the working ) so plz help me and show all the steps
btw this is differentiation

w=3r^3 -2r^2 +r-3

s=3t^2-4t-2

Answer 1

for differentiation, the general rule is
nx^n-1 if there is a constant, you can use the constant multiple rule and put it to the side to multiply at the end, if you have a constant, it becomes 0. Using your info you get the following:

w'(r)=3(3r^3-1)-2(2r^2-1)+(1r^1-1)-0
=3(3r^2)-2(2r^1)+(r^0)-0
=9r^2-4r+1

using the same methodology
s'(t)=3(2t^2-1)-4(1t^1-1)-0
=3(2t^1)-4(t^0)-0
=6t-4

Hope this helps!

Answer 2

dw/dr = 9r² - 4r +1

ds/dt = 6t - 4

It's like dy/dx. w=y and r=x. So it's dw/dx. Same with s and t.

dw means a little (infintesimal) change in w. dr means a little change in r. The slope is that little change in w (dw), divided by the little change in r (dr). Thus dw/dr.
Slope function. Change in Y over change in X.

Answer 3

dw/dr =9r^2-4r+1

ds/dt = 6t-4

Answer 4

yea get a calculator

Answer 5

What?!?!?!