Please help me!!! expand and simplify 3(2p+1)+2(3p-1) Can you describe in detail how to do it aswell please?

Question

expand and simplify 3(2p+1)+2(3p-1)

Answer 1

3(2p+1) + 2(3p-1) =

3* 2p + 3*1 + 2*3p - 2*1
= 6p + 3 + 6p -2
= 12p+1
There's nothing much to describe as it is self explanatory. if you still don't get it ,you have to go back to grade 1 mathematic classes

Answer 2

3(2p+1)+2(3p-1) Distributive Property
6p+3+6p-2
12p+1

Answer 3

Proceed by multiplying the factors:
3(2p +1)+ (2(3p -1)=
6p +3 +6p-2=
12p+ 1=
12p= -1
p =-1/12

Answer 4

To expand, multiply each term. So ,multiply 3(2p+1) and 2(3p-1) SEPARATELY

3(2p+1) = 3 (2p) + 3 (1)

= 6p + 3

You can do the other one for practice.

Then you should get
3(2p+1)+2(3p-1) = 6p+3+6p-2

To simplify, put the terms with p together, and the same with the constants.

6p+3+6p-2 = 6p + 6p + 3 - 2
The final answer is

3(2p+1)+2(3p-1) = 12p + 1

Answer 5

There is no need for people to be rude about going back to elementary classes. The question setter is unsure how it is done.
3(2p+1) +2(3p-1)

The parts inside the brackets are multiplied individually by the number outside the bracket
so 6p+3 for the first bracket
and 6p -2 for the second bracket

Put them together
6p+3+6p-2
Now group like terms together
makes 12p+1

Answer 6

just multiply the outer number with everything inside the brackets.. for ex:

3*2p + 3*1 + 2*3p - 2*1
6p + 3 + 6p - 2
12p + 1

Answer 7

3(2p+1)+2(3p-1)
6p+3+6p-2
=12p+1

just multiply it separatly

3*2p=6p
3*1=3
2*3p=6p
2*1=2

then,add the two variables[6p+6p]
& subtract[3-2]
=12p+1

(in algebra, a letter of the alphabet is used to represent a quantity that is unknown or one that can change, or vary this letter is called a variable.

Answer 8

3(2p+1) + 2(3p-1)
= (6p + 3) + (6p - 2)
= 6p + 3 + 6p - 2
= 12p + 1

Answer 9

3(2p+1)+2(3p-1)

6p+3+6p-2

12p+ 1

Answer 10

=3(2p+1)+2(3p-1)
=6p+3+6p-2
=12p+1

erm... there is nothing much to explain about, just multiply and just simplify it.