In triangle ABC, BC = sin A. Find the radius of the circumcircle and the lengths of the other two sides...?

Question

Sorta confused...help? Explain it and show work with explination please!

Question: In triangle ABC, BC = sin A. Find the radius of the circumcircle and the lengths of the other two sides in terms of the angles.

Answer 1

BC is the side opposite the angle A so the Law of Sines applies.

Let
R = radius of the circumcircle

a/sinA = BC/sinA = 2R

1 = 2R
R = 1/2

The radius of the circumcircle is 1/2.

The entire Law of Sines says:

a/sinA = b/sinB = c/sinC = 2R

a/sinA = b/sinB = c/sinC = 1