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A. Low ionization energy and good electrical conductivity?

B. High ionization energy and poor electrical conductivity?

C. High ionization energy and good electrical conductivity?

D. Low ionization energy and poor electrical conductivity?

2007-11-09 14:46:58 · 5 answers · asked by Chris M 1 in Science & Mathematics Chemistry

5 answers

It would be B. Here is the website I used to figure it out...
http://chemistry.about.com/library/weekly/aa010103b.htm

2007-11-09 14:52:27 · answer #1 · answered by נєѕѕι¢α (ανα'ѕ мσмму) 5 · 3 0

B 100% sure - remember Ionization energy increases across a period and decreases down a period. Nonmetals are located to the far right of the periodic table therefore they must have high ionization energy.

Ionization energy is the amount of energy required to remove an electron from its valence orbit. *note nonmetals are in the p block which holds a max of 6 electrons.

2007-11-09 14:54:40 · answer #2 · answered by holiday 3 · 2 0

If by ionisation energy you mean first ionisation energy (The energy to remove 1 electron from an orbit), which they usually do, then B is the answer. With a few exceptionslike graphite, no non-metal can condut, and further to the right of hte periodic table you are, the more protons you have, so it is harder to remove electrons.

2007-11-09 14:54:02 · answer #3 · answered by Bob B 7 · 1 0

B. Moving across a period, the atomic radius decreases. This is due to the fact that the nucleus pulls the electrons closer to itself. Therefore, a greater energy is needed to become an ion from an atom by removing an electron.

2007-11-09 15:31:35 · answer #4 · answered by Anonymous · 2 0

B.high ionization energy and poor electrical conductivity?
i am taking a take home chapter 6 test and i just came and finished this exact problem for chemistry ..i agree with the others that its B(just think of it as things that are "non" something is mostly bad so electrical conductivity is poor but the ionization energy is high)hope that this helped

2007-11-11 15:27:12 · answer #5 · answered by Emily L 3 · 2 0

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