Algebraic and Graphical solution for vectors and scalar?

Question

ok, here's my physics problem, I have to do an assignment that involves finding resultant displacement, average velocity and average speed. There is one question where I have to solve BOTH algebraically and graphically.

The problem is, I'm not getting the same answer. I know that it's ok to be a bit off since the measurements for the graphical solution might not be exact, but I am way off. The two answers are completely different.

In the question, the given information is:
[delta] d1 = 125.75 m, 35 [degrees] E of N taking 14.50 secs
[delta] d2 = 345.0 m, 65 [degrees] W of S taking 55.35 secs

For my algebraic solution, my resultant displacement was 244.33 m (I'm not sure which angle I should calculate, so please help!)

For my graphical solution, my resultant displacement was 230 m (again, I dont know the angle and direction).

I'm thinking that my graphical solution is wrong because my triangle looks pretty bad. Any help in finding the resultant displacement would be nice and thx!!

Answer 1

125.75 sin 35 = 72.13 toward East.
125.75 cos 35 = 103 toward North.

345 sin 65 = 312.68 toward West
345 cos 65 =145 .8 toward South

Net displacement toward South is 145.8 - 103 = 42.8
Net displacement toward West = 312.68 - 72.13 = 240.55

Resultant of these two is √ [42.8 ^2 + 240.55 ^2]
= 244.33 m
tan θ = 240.55/ 42.8 :{WEST / South}
θ = 79.9° West of South.
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In the graph draw the answer (244.33 at angle 79.9 West of South and check. .

Answer 2

A scalar volume could have at maximum one single length. it could have a direction ( forward and backwards) yet no greater advantageous than that. So use those policies. Can time have greater advantageous than one length or in basic terms a single one? Can time have a cost in the two the forward or backward direction yet no longer something different than this? if so then it relatively is seen to be a scalar. A vector has varied self sustaining dimensions the place there are a number of circumstances wherein a million+a million would not equivalent 2 ( nor 0 the two). i.e a million North + a million east would not equivalent 2 in any direction. provided that we artificially constrain the circulation alongside a single song ( railway song?) then the circulation would be seen as a scalar.

Answer 3

d1y = 125.75cos35 ≈ 103.0084
d2y = - 345.0cos65 ≈ -145.8033
dy ≈ - 42.79493
d1x = 125.75sin35 ≈ 72.12724
d2x = - 345.0sin65 ≈ - 312.6762
dx ≈ - 240.5489
d ≈ 244.33 m @ 79.9 W of S