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ok, i have to solve for x in the equation
-2|3x+7|+2>-4

Im really having problems and i can usually do these pretty good, can someone please walk me through this one, also the | is absolute value in case you have problems making this symbol out.

Thanks is advance :)

2007-11-09 13:10:17 · 8 answers · asked by chuckt 3 in Education & Reference Homework Help

8 answers

Subtract 2 from both sides
-2|3x+7|>-6
Divide -2 from both sides, results in a sign change.
|3x+7|<3
3x+7<3 and 3x+7>-3
3x<-4
x< -4/3

3x+7>-3
3x>-10
x> -10/3

So -10/3

2007-11-09 13:15:53 · answer #1 · answered by Anonymous · 2 0

x>-1 2/3

2007-11-09 13:14:29 · answer #2 · answered by doubledutchmania 2 · 0 1

First, what ever is in an absolute value sign is how far away the equation is from zero.

So, since both are positive, you can change the absolute value signs to ( )

The question now reads

-2(3x+7)+2>-4

Now, distribute the -2

-6x + -14 + 2 >-4

Add all common values

-6x + - 12 > -4

Now add 12 to both sides

-6x > 8

Now divide by -6 on both sides

-6x/-6 > 8/-6

=====================

x > -8/6

x = -8/6

2007-11-09 13:18:31 · answer #3 · answered by free_n08 2 · 1 1

-2|3x+7|+2>-4
-2|3x+7|+2 -2>-4 -2
-2|3x+7| >-6
|3x + 7| < 3

3x + 7 < 3
3x < -4
x < -4/3
first answer

-3x - 7 < 3
-10 < 3x
-10/3 < x
second answer

-10/3 < x < -4/3

2007-11-09 13:20:58 · answer #4 · answered by Steve A 7 · 0 0

i think this is how you do it!
Subtract 2 from both sides
-2|3x+7|>-6
Divide -2 from both sides, results in a sign change.
|3x+7|<3
3x+7<3 and 3x+7>-3
3x<-4
x< -4/3

3x+7>-3
3x>-10
x> -10/3

So -10/3

2007-11-09 13:19:26 · answer #5 · answered by MelissaC 2 · 0 1

ok, first you divide the -2 from both sides

-2|3x+7|+2>-4............ |3x+7|+2<2 (dont forget to reverse the ineqality)

then you suptract the 2 from both sides

|3x+7|+2<2............ |3x+7|<0

then you solve for 0

3x+7<0
-7 -7

3x<-7
x<-1.5!!!!!!

2007-11-09 13:23:15 · answer #6 · answered by that one girl from tha city 1 · 0 0

3x>-11

2007-11-09 13:14:05 · answer #7 · answered by Sara Rose 2 · 0 2

try -1..by the way what grade r u in?

2007-11-09 13:14:49 · answer #8 · answered by Anonymous · 0 2

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