Find the units digit of 7 to the power of 2007?

Answer 1

3
7^0 = 1
7^1 =7
7^2 = 49
7^3 = 343
After that the units digit keeps alternating in the pattern 1, 7, 9, 3, 1, 7, 9, 3, etc
So 7^2007 has the same units digit as 7^7 has the same units digit as 7^3. That units digit is 3.

Answer 2

The question is find the units digit while evaluating 7 ^ 2007 ie 7 * 7 * 7 .... .... 2007 times.

When you raise 7 to the power of 0 , 1 , 2 and so , it forms a pattern with the last digit (Units)

7^0 = 1
7^1 = 7
7^2 = 49
7^3 = 343
7^4 = 2401
and so on
therefore the last digit in 7^7 would be 3.

Answer 3

We see that

7^1 = 7 Unit's digit is 7
7^2 =49 Unit's digit is 9
7^3 = 343 Unit's digit is 3
7^4 = 2401 Unit's digit is 1

If we go on calculating this sequence we can notice that these 4 digits at unit's place repeat after every 4 powers. Hence the in the given Power (2007) this sequance of 7,9, 3, 1 will repeat for 343 times up to the step 7^2004. Hence the next ie 7^2005 will have 7 at its unit's place, while the next 7^2006 will have 9, and 7^2007 will have 3 at it's unit's place

Answer 4

neither your question nor lina's answer was comprehensible,request elucidate.

i got it,thanks to lina & dt